Tag Archives: Percentile

Exam P Practice Problem 82 – Estimating the Median Weight of Bears

Problem 82-A

A wildlife biologist wished to estimate the median weight of bears in Alaska. The weights of the bear population he studied follow a continuous distribution with an unknown median M. He captured a sample of 15 bears. Let Y_5 be the weight (in pounds) of the fifth smallest bear in the sample of 15 captured bears. Let Y_{11} be the weight (in pounds) of the fifth largest bear in the sample.

Calculate the probability that the median M is between Y_5 and Y_{11}, i.e., P(Y_5<M<Y_{11}).

      \displaystyle (A) \ \ \ \ \ \ \ \ \ \ \ \ 0.5000

      \displaystyle (B) \ \ \ \ \ \ \ \ \ \ \ \ 0.7899

      \displaystyle (C) \ \ \ \ \ \ \ \ \ \ \ \ 0.8218

      \displaystyle (D) \ \ \ \ \ \ \ \ \ \ \ \ 0.8815

      \displaystyle (E) \ \ \ \ \ \ \ \ \ \ \ \ 0.9232

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Problem 82-B

The wildlife biologist in Problem 82-A also wishes to estimate \tau_{75}, the seventy fifth percentile of the weights of bear population he studied. Let Y_{10} be the weight of the tenth smallest bear in the sample of 15 captured bears. Let Y_{14} be the weight of the second largest bear in the sample of 15 bears.

Calculate the probability that \tau_{75} is between Y_{10} and Y_{14}, i.e., P(Y_{10}<\tau_{75}<Y_{14}).

      \displaystyle (A) \ \ \ \ \ \ \ \ \ \ \ \ 0.6155

      \displaystyle (B) \ \ \ \ \ \ \ \ \ \ \ \ 0.7500

      \displaystyle (C) \ \ \ \ \ \ \ \ \ \ \ \ 0.7715

      \displaystyle (D) \ \ \ \ \ \ \ \ \ \ \ \ 0.8383

      \displaystyle (E) \ \ \ \ \ \ \ \ \ \ \ \ 0.9232

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\copyright \ 2014 \ \text{ Dan Ma}

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Exam P Practice Problem 66 – Median Cholesterol Level

Problem 66-A

The blood cholesterol levels of men aged 55 to 64 are normally distributed with mean 225 milligrams per deciliter (mg/dL) and standard deviation 39.5 mg/dL.

A medical researcher is planning a clinical study targeting men from the age group of 55 to 64 who have high blood cholesterol levels (above 240 mg/dL).

What is the median cholesterol level of the men in the target population of this medical study?

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      \displaystyle (A) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 225 \ \text{ mg/dL}

      \displaystyle (B) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 249 \ \text{ mg/dL}

      \displaystyle (C) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 262 \ \text{ mg/dL}

      \displaystyle (D) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 284 \ \text{ mg/dL}

      \displaystyle (E) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 294 \ \text{ mg/dL}

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Problem 66-B

The blood cholesterol levels of women aged 55 to 64 are normally distributed with mean 190 milligrams per deciliter (mg/dL) and standard deviation 40 mg/dL.

A medical researcher is planning a clinical study targeting women from the age group of 55 to 64 who have borderline high blood cholesterol levels (between 200 and 240 mg/dL).

What is the median cholesterol level of the women in the target population of this medical study?

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      \displaystyle (A) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 214 \ \text{ mg/dL}

      \displaystyle (B) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 216 \ \text{ mg/dL}

      \displaystyle (C) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 218 \ \text{ mg/dL}

      \displaystyle (D) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 220 \ \text{ mg/dL}

      \displaystyle (E) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 225 \ \text{ mg/dL}

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\copyright \ 2013

Exam P Practice Problem 52 – Reliability of Refrigerators

Problem 52-A

The time from initial purchase to the time of the first major repair (in years) for a brand of refrigerators is modeled by the random variable Y=e^X where X is normally distributed with mean 1.2 and variance 2.25.

A customer just bought a brand new refrigerator of this particular brand. The refrigerator came with a two-year warranty. During the warranty period, any repairs, both minor and major, are the responsibilities of the manufacturer.

What is the probability that the newly purchased refrigerator will not require major repairs during the warranty period?

      \displaystyle (A) \ \ \ \ \ \ \ \ 0.2451

      \displaystyle (B) \ \ \ \ \ \ \ \ 0.2981

      \displaystyle (C) \ \ \ \ \ \ \ \ 0.3669

      \displaystyle (D) \ \ \ \ \ \ \ \ 0.6331

      \displaystyle (E) \ \ \ \ \ \ \ \ 0.7549

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Problem 52-B

The time from initial purchase to the time of the first major repair (in years) for a brand of refrigerators is modeled by the random variable Y=e^X where X is normally distributed with mean 0.8 and standard deviation 1.5.

What is the median length of time (from initial purchase) that is free of any need for major repairs?

      \displaystyle (A) \ \ \ \ \ \ \ \ 0.80 \text{ years}

      \displaystyle (B) \ \ \ \ \ \ \ \ 2.23 \text{ years}

      \displaystyle (C) \ \ \ \ \ \ \ \ 3.50 \text{ years}

      \displaystyle (D) \ \ \ \ \ \ \ \ 4.71 \text{ years}

      \displaystyle (E) \ \ \ \ \ \ \ \ 6.86 \text{ years}

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